如何从矩阵中删除所有带有NA的行? [英] How to remove all rows with NA from a matrix?

问题描述

我有 :一个矩阵 y ，它有两列(行数不同，取决于输入参数).第一列中的所有元素都是整数.

I have: A matrix y and it has two columns (the number of rows is different and depends on the input parameters). All the elements in the first columns are integers.

我需要 :如果第二列的元素为NA，则需要为每一行删除该行.

I need: for each row if the element of the second column is NA, I need to remove this row.

我该怎么办?我唯一的想法是创建另一个矩阵，如果第一个矩阵中的一行没有NA，则将其添加到第二个矩阵中.但是我敢打赌，R中有一种更优雅的方法.

How can I do it? My only idea is to create another matrix and if a row from my first matrix doesn't have NA, add it to the second matrix. But I bet there's a more elegant way of doing so in R.

谢谢！

推荐答案

包含一些组成数据的示例:

An example with some made up data:

m <- matrix(c(1:3,c(1,NA,4)),ncol=2)
m[!is.na(m[,2]),]

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