我如何使用opencv python根据其位置生成被检测对象的热图 [英] how do i generate a heat map of a detected object based on its position using opencv python

问题描述

我需要根据对象的位置生成对象的热图 例如:在视频帧中检测到的绿球.如果它长时间停留在某个位置，则该位置应为红色，并且球在短时间内通过的帧中的位置必须为蓝色，这样我就需要生成一个热图.预先感谢

I need to generate the heat map of a object based on its position example: the detected green ball in a video frame . If it stays in a position for a long duration then that place should be red and the positions in the frame where the ball has passes for a short duration must be in blue in that way i need to generate a heat map . Thanks in advance

推荐答案

在这里您可以做的是

1)首先定义一个热图作为图像的大小

1) First define a heatmap as the size of the image

  heatmap = np.zeros_like(img[:,:,0]).astype(np.float)

2)由于您已经具有检测到的对象及其位置，因此，在热图中，将1添加到对象边界框中的所有像素.

2) Since you already have the detected object and its position, in the heatmap, add 1 to all pixels in the bounding box of the object.

heatmap[box[0][1]:box[1][1], box[0][0]:box[1][0]] += 1

3)然后，您可以通过将热图中阈值以下的所有像素设置为0来应用阈值.您可以将阈值选择为1，以便边界框内的区域保留在热图中 >

3) you can than apply thresholding by setting all pixels which are below a threshold value in the heatmap to be 0. You can choose the threshold value to be 1 so that the region inside your bounding box remains in the heatmap

heatmap[heatmap <= threshold] = 0

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