在PHP中的方括号之间捕获文本 [英] Capturing text between square brackets in PHP
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问题描述
我需要某种方式来捕获方括号之间的文本.因此,例如,以下字符串:
I need some way of capturing the text between square brackets. So for example, the following string:
[This] is a [test] string, [eat] my [shorts].
可用于创建以下数组:
Array (
[0] => [This]
[1] => [test]
[2] => [eat]
[3] => [shorts]
)
我有以下正则表达式,/\[.*?\]/
,但它仅捕获第一个实例,所以:
I have the following regex, /\[.*?\]/
but it only captures the first instance, so:
Array ( [0] => [This] )
如何获得所需的输出?请注意,方括号是从不嵌套的,因此不必担心.
How can I get the output I need? Note that the square brackets are NEVER nested, so that's not a concern.
推荐答案
匹配所有带括号的字符串:
Matches all strings with brackets:
$text = '[This] is a [test] string, [eat] my [shorts].';
preg_match_all("/\[[^\]]*\]/", $text, $matches);
var_dump($matches[0]);
如果您想要不带括号的字符串:
If You want strings without brackets:
$text = '[This] is a [test] string, [eat] my [shorts].';
preg_match_all("/\[([^\]]*)\]/", $text, $matches);
var_dump($matches[1]);
不带括号的替代版本,匹配速度较慢(使用"*"代替"[^]"):
Alternative, slower version of matching without brackets (using "*" instead of "[^]"):
$text = '[This] is a [test] string, [eat] my [shorts].';
preg_match_all("/\[(.*?)\]/", $text, $matches);
var_dump($matches[1]);
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