将void *指针设置为等于整数 [英] Setting void * pointer equal to an integer

问题描述

我对以下代码有疑问:

int age = 20;
void * pointer;
pointer = alloc(sizeof(int), 0)

pointer = (void*) age;

它如何工作?

pointer的值是什么?

这段代码在一行中会发生什么:

What happens with this piece of code in terms of the line :

pointer = (void*) age;

推荐答案

此代码完全不执行任何操作.

This code accomplishes exactly nothing.

首先，您使用非标准的分配方法为int的大小分配了一个指针.

First, you allocated a pointer for a size of int, using non-standard allocation methods.

然后，您将指针分配给指向地址0x14的地址，该地址可能不包含任何有效信息，并且如果尝试取消引用它，则会给出SEGFAULT.

Then, you assign that pointer to point to the address 0x14, which probably doesn't contain any valid information, and would give you a SEGFAULT if you attempted to dereference it.

第三，您泄漏了alloc用于指针的初始内存，这从来都不是一件好事.

Third, you leak the initial memory you alloc'd for pointer, which is never a good thing.

总体来说，这是一个非常糟糕的设计模式.

Overall, a VERY bad design pattern.

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