以无符号整数存储缓冲区的地址； [英] Storing address of buffer in an unsigned integer;

问题描述

我有一个内存缓冲区，我想将其地址存储为无符号整数值.

I have a memory buffer whose address i want to store in an unsigned integer value.

uint8_t* _buff = new uint8_t[1024];
uint64_t* _base_addr = (uint64_t *)_buff;

我希望将_buff或_base_addr所指向的位置的地址(无论如何都是同一位置)存储在uint32_t值中.

I want the address of the location pointed by _buff or _base_addr (anyhow it is the same location) to be stored in say uint32_t value.

这样，当我读取整数值时，它便给了我地址. 怎么办呢?

So that when i read the value of integer it gives me the address. How can this be done ?

推荐答案

您无法在"say" uint32_t变量中存储地址，因为该地址可能不适合-在64位系统上，指针需要64位存储.而不是固定大小，请使用C99(<stdint.h>)或C ++ 11(<cstdint>)的uintptr_t.

You cannot store an address in "say" uint32_t variable, as the address might not fit - on 64-bit systems the pointers require 64 bits of storage. Instead of fixing the size, use the uintptr_t of C99 (<stdint.h>) or C++11 (<cstdint>).

要将地址存储在这样的整数变量中，请使用

To store the address in such an integer variable, use

uintptr_t variable = (uintptr_t)pointer;

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