在Python 3中生成具有要求的随机字符串 [英] generating random string with requirements in Python 3

问题描述

我正在尝试为具有以下密码要求的Active Directory生成随机密码:至少8个字符，至少一个特殊字符，至少一位数字，至少一个小写字母和至少一个大写字母.

使用以下代码，我可以生成一个随机密码，并检查它是否包含特殊字符.生成新密码，直到找到特殊字符为止.

special_char = "!@%/()=?+.-"

password_string = "".join([random.choice(string.ascii_lowercase + string.ascii_digits + string.ascii_uppercase + special_char) for n in range(8)])

while any(c in password_string for c in special_char) is not True:
    password_string = "".join([random.choice(string.ascii_lowercase + string.ascii_digits + string.ascii_uppercase + special_char) for n in range(8)])

以下内容的问题是，它仅检查特殊字符并生成新密码可能会摆脱其他要求(假设它们已经存在).如何才能有效地实施AD密码要求?感谢您的帮助.

解决方案

您可以首先生成一个匹配的密码，方法是先选择一个特殊的字符和一个数字(以相同的方式分别选择一个小写字母和一个大写字母) ，填满所有内容，最后重新整理顺序:

pwlist = ([random.choice(special_char),
           random.choice(string.ascii_digits),
           random.choice(string.ascii_lowercase),
           random.choice(string.ascii_uppercase),
          ]  
         + [random.choice(string.ascii_lowercase
                          + string.ascii_uppercase
                          + special_char
                          + string.ascii_digits) for i in range(4)])
random.shuffle(pwlist)
pw = ''.join(pwlist)

I'm trying to generate random passwords for the Active Directory that has the following password requirements: at least 8 characters, at least one special character, at least one digit, at least one lowercase and at least one uppercase.

With the following code I'm able to generate a random password and check whether it contains a special character. New password is generated until a special character is found.

special_char = "!@%/()=?+.-"

password_string = "".join([random.choice(string.ascii_lowercase + string.ascii_digits + string.ascii_uppercase + special_char) for n in range(8)])

while any(c in password_string for c in special_char) is not True:
    password_string = "".join([random.choice(string.ascii_lowercase + string.ascii_digits + string.ascii_uppercase + special_char) for n in range(8)])

The problem with the following is that it's only checking for the special character and generating a new password might get rid of the other requirements assuming they existed. How could I implement the AD password requirements efficiently? Thanks for any help.

解决方案

You could generate a matching password to begin with, by first picking a special char and a digit (and one lower- and one uppercase letter in the same manner), filling up with anything, and shuffling the order in the end:

pwlist = ([random.choice(special_char),
           random.choice(string.ascii_digits),
           random.choice(string.ascii_lowercase),
           random.choice(string.ascii_uppercase),
          ]  
         + [random.choice(string.ascii_lowercase
                          + string.ascii_uppercase
                          + special_char
                          + string.ascii_digits) for i in range(4)])
random.shuffle(pwlist)
pw = ''.join(pwlist)

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