在C ++ 11中生成一个随机字符串? [英] generate a random string in C++11?

问题描述

我需要使用C ++ 11生成随机字符串的帮助.

I need help with generating a random string using C++11.

如果您能帮助我，我不知道该如何继续.

I don't know how to continue with that, if you can help me please.

#include <random>
char * random_string()
{

        static const char alphabet[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";
    static const MAX_LEN = 32;  //MAX LENGTH OF THE NEW CHAR RETURNED
    int stringLength = sizeof(alphabet)/sizeof(alphabet[0]);

    for (int i = 0; i<=MAX_LEN;i++)
    {
        //now i don't know what i need to do help!
    }

    static const char test[MAX_LEN];

    return test;

}

推荐答案

返回一个 std :: string 而不是原始的 char * .根据需要填充字符串以开始，然后将其随机播放.

Return a std::string rather than a raw char *. Populate the string as needed to start, and then shuffle it.

例如；

#include <random>
#include <string>

std::string random_string()
{
     std::string str("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz");

     std::random_device rd;
     std::mt19937 generator(rd());

     std::shuffle(str.begin(), str.end(), generator);

     return str.substr(0, 32);    // assumes 32 < number of characters in str         
}

如果您真的需要从 std :: string 提取原始的 const char * ，请使用其 c_str()成员函数.

If you really need to extract a raw const char * from a std::string use its c_str() member function.

int main()
{
    std::string rstr = random_string();

    some_func_that_needs_const_char_pointer(rstr.c_str());
}

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