如何在C ++中将int转换为wchar_t *? [英] How to concat an int to a wchar_t* in C++?

问题描述

我必须创建和写入N个文件，每个人都必须以整数结尾来标识它.

I have to create and write on N files, everyone must have an integer ending to identificate it.

这是我的代码:

for(int i=0; i<MAX; i++)
{
    uscita.open("nameFile"+i+".txt", ios::out); 
    uscita <<  getData() << endl;
    uscita.close();     
}

这就是我想要在执行后在目录中找到的内容:

And that's what I would like to find in my directory after execution:

nameFile0.txt
nameFile1.txt
nameFile2.txt
...
nameFileMAX.txt

上面的代码的问题是我得到了编译错误:

The problem of the above code is that I get the compilin' error:

错误C2110:'+'无法添加两个指针

error C2110: '+' Impossible to add two pointers

如果我尝试为该名称创建一个字符串，则会出现另一个问题:

If I try to create a string for the name, another problem comes in:

string s ="nameFile"+i+".txt";
uscita.open(s, ios::out); 

问题是:

错误C2664:您无法从字符串转换为const wchar_t*

我该怎么办?如何创建具有不同名称的文件，将int包含为wchar_t*?

What can I do? How can I create files with different names concating int to wchar_t*?

推荐答案

您可以使用wstringstream

std::wstringstream wss;
wss << "nameFile" << i << ".txt";
uscita.open(wss.str().c_str(), ios::out);

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