如何转置不同大小的红宝石阵列? [英] How can I transpose different sized ruby arrays?

问题描述

我有一个数组:

arr=[[1,2,3],[4,5],[6]],

我有以下代码:

arr.transpose 

但是它不起作用，如何解决?

but it doesn't work,how to solve it?

我得到

 [[1,2,3],[4,5],[6]].transpose
IndexError: element size differs (2 should be 3)
    from (irb):13:in `transpose'
    from (irb):13
    from /home/durrant

我的解决方案:

arr.reduce(&:zip).map(&:flatten)

输出:

[[1, 4, 6], [2, 5, nil], [3, nil, nil]]

推荐答案

一个小时前发布(但已删除)了一个类似的答案:

A similar answer was posted (but deleted) an hour earlier:

arr = [[1, 2, 3], [4, 5], [6]]

arr[0].zip(*arr[1..-1])
#=> [[1, 4, 6], [2, 5, nil], [3, nil, nil]]

以上等同于:

[1, 2, 3].zip([4, 5], [6])

此方法假定您的第一个子数组始终是最长的.否则结果将被截断:

This approach assumes that your first sub-array is always the longest. Otherwise the result will be truncated:

arr = [[1, 2], [3, 4, 5], [6]]

arr[0].zip(*arr[1..-1])
#=> [[1, 3, 6], [2, 4, nil]]  missing: [nil, 5, nil]

这篇关于如何转置不同大小的红宝石阵列?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！