红宝石嵌入到每个做+阵列串联 [英] Ruby nested each do + array concatenation

问题描述

*新手歉意。

以下code：

dates = ['Transaction_Date','Renewal_Date']
dateoptions = ['Year','Month','Date']
word1 = "Amount"

dates.each do |x|
  puts word1 + " by " + x
  end

返回

Amount by Transaction_Date
Amount by Renewal_Date

我想结果是日期和dateoptions的串联，像这样

I would like the outcome to be a concatenation of the dates and dateoptions, like so

Amount by Transaction_Date (Year)
Amount by Transaction_Date (Month)
Amount by Transaction_Date (Date)
Amount by Renewal_Date (Year)
Amount by Renewal_Date (Month)
Amount by Renewal_Date (Month)

我想在做一个嵌套的每一个做，但我仍然不知道如何处理这两个数组的串联。

I was thinking of doing a nested "each do" but I still wouldn't know how to address the concatenation of the two arrays.

鸭preciate你输入

Appreciate your input

推荐答案

您需要使用嵌套的每个：

dates = ['Transaction_Date','Renewal_Date']
dateoptions = ['Year','Month','Date']
word1 = "Amount"

dates.each do |d|
  dateoptions.each do |option|
    puts "#{word1} by #{d} (#{option})"
  end
end

您也可以使用 阵列＃产品

dates.product(dateoptions) do |d, option|
  puts "#{word1} by #{d} (#{option})"
end

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