NG-显示数组是否包含某个值，而不包含另一个值 [英] NG-Show if array contains a certain value and not another

问题描述

我拥有3个用户权限-管理员，用户和编辑者.设置方法是:

I have an 3 user rights - Admin, User, and Editor. The way this is setup is:

如果您是Admin，则返回值为roles: ["Admin", "User", "Editor"]

If you are an Admin the return is roles: ["Admin", "User", "Editor"]

如果您是User，则返回值为roles: ["User"]

If you are an User the return is roles: ["User"]

如果您是Editor，则返回值为roles: ["User", "Editor"]

If you are an Editor the return is roles: ["User", "Editor"]

现在我所拥有的是另外两个的ng-show="object.roles.length < 2" = User等.

Now what I have now is ng-show="object.roles.length < 2" = User and etc. for the other two.

我敢肯定，有一种更好/更聪明的方法可以做到这一点，或者也许更容易做到这一点.我只是不确定如何去做不同的事情.感谢您的建议.

I am sure there is a better/smarter way to do this or maybe it is easier to do it this way. I am just not sure how to go about it differently. Thanks for the suggestions.

推荐答案

那不是一个好主意.您正在通过计算数组长度来管理应用程序的UI.如果这改变了怎么办?我建议始终验证是否拥有所需的角色.例如ng-show="hasRole('User')"

That is not a good idea. You are managing your app's UI by counting an array length. What if this changes? I would suggest to verify always if the role needed is owned. For example ng-show="hasRole('User')"

$scope.hasRole = function(role){
     var indexOfRole = $scope.roles.indexOf(role); // or whatever your object is instead of $scope.roles
     if (indexOfRole === -1)
          return false;
     else
          return true;
}

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