将Boost FileSystem3迭代器转换为const char * [英] Casting a Boost FileSystem3 iterator to a const char*
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问题描述
我正在使用Boost FileSystem 3遍历目录中的某些文件,并且需要将文件名强制转换为另一个库的char *,不幸的是我缺少C ++ foo,有人可以帮忙吗?
I'm looping over some file in a directory using Boost FileSystem 3 and I need to cast the filename to a char* for another lib, Unfortunately my C++ foo is lacking, can anyone help ?
int main(int argc, char* argv[])
{
path p (argv[1]); // p reads clearer than argv[1] in the following code
try
{
if (exists(p)) // does p actually exist?
{
if (is_regular_file(p)) // is p a regular file?
cout << p << " size is " << file_size(p) << '\n';
else if (is_directory(p)) // is p a directory?
{
cout << p << " is a directory containing:\n";
typedef vector<path> vec; // store paths,
vec v; // so we can sort them later
copy(directory_iterator(p), directory_iterator(), back_inserter(v));
sort(v.begin(), v.end()); // sort, since directory iteration
// is not ordered on some file systems
for (vec::const_iterator it (v.begin()); it != v.end(); ++it)
{
cout << " " << *it << '\n';
/****************** stuck here **************************/
// I need to cast *it to a const char* filename
/****************** stuck here **************************/
}
}
else
cout << p << " exists, but is neither a regular file nor a directory\n";
}
else
cout << p << " does not exist\n";
}
catch (const filesystem_error& ex)
{
cout << ex.what() << '\n';
}
return 0;
}
推荐答案
表达式*it
返回类型为path
的对象,因此您必须执行以下操作:
The expression*it
returns an object of type path
, so you've to this:
const std::string & s = (*it).string();
const char *str = s.c_str(); //this is what you want
或者也许您想使用其他转换功能,如下所示:
Or maybe you want to use other conversion functions, as listed below:
const std::string & string() const;
std::string native_file_string() const;
std::string native_directory_string() const;
选择任何您要使用的.首先阅读文档,了解它们各自返回的内容:
Choose whichever you want to use. Read the documentation first as to what each of them returns:
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