创建带有boost :: bind()的boost :: thread或不创建 [英] Creating a boost::thread with boost::bind() or without

问题描述

有些人似乎使用boost :: bind()函数启动boost :: threads，就像在以下问题的公认答案中一样:

Some people seem to launch boost::threads using the boost::bind() function, like in the accepted answer of the following question:

使用Boost线程和非静态类函数

其他人根本不使用它，例如在对该问题最支持的答案中:

Whereas other people don't use it at all, like in the answer with the most upvotes of this question:

启动A的最佳方法线程作为C ++类的成员?

那么，如果存在的话，有什么区别?

So, what's the difference, if it exists?

推荐答案

如下面的代码所示，该代码可以编译并提供预期的输出，对于使用带有自由功能的boost :: thread，boost :: bind完全没有必要，成员函数和静态成员函数:

As you can see by the code below that compile and gives the expected output, boost::bind is completely unnecessary for using boost::thread with free functions, member functions and static member functions:

#include <boost/thread/thread.hpp>
#include <iostream>

void FreeFunction()
{
  std::cout << "hello from free function" << std::endl;
}

struct SomeClass
{
  void MemberFunction()
  {
    std::cout << "hello from member function" << std::endl;
  }

  static void StaticFunction()
  {
    std::cout << "hello from static member function" << std::endl;
  }
};

int main()
{
  SomeClass someClass;

  // this free function will be used internally as is
  boost::thread t1(&FreeFunction);
  t1.join();

  // this static member function will be used internally as is
  boost::thread t2(&SomeClass::StaticFunction);
  t2.join();

  // boost::bind will be called on this member function internally
  boost::thread t3(&SomeClass::MemberFunction, someClass);
  t3.join();
}

输出:

hello from free function
hello from static member function
hello from member function

构造函数中的内部绑定会为您完成所有工作.

The internal bind in the constructor does all the work for you.

仅添加了一些关于每种函数类型会发生什么的额外注释. (希望我已经正确地阅读了源代码！)据我所知，在外部使用boost :: bind不会导致它也加倍并在内部被调用，因为它将按原样通过.

Just added a few extra comments on what happens with each function type. (Hopefully I've read the source correctly!) As far as I can see, using boost::bind externally will not cause it to also double up and be called internally as it will pass through as is.

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