提升string_algo的to_upper函数不考虑语言环境 [英] boost to_upper function of string_algo doesn't take into account the locale

问题描述

我对string_algo软件包中的功能有疑问.

I have a problem with the functions in the string_algo package.

考虑这段代码:

#include <boost/algorithm/string.hpp>
int main() {
   try{
      string s = "meißen";
      locale l("de_DE.UTF-8");
      to_upper(s, l);
      cout << s << endl;
   catch(std::runtime_error& e){
      cerr << e.what() << endl;
   }

   try{
      string s = "composición";
      locale l("es_CO.UTF-8");
      to_upper(s, l);
      cout << s << endl;
   catch(std::runtime_error& e){
      cerr << e.what() << endl;
   }
}

此代码的预期输出为:

MEISSEN
COMPOSICIÓN

但是我唯一得到的是

MEIßEN
COMPOSICIóN

因此，很明显，没有考虑区域设置.我什至尝试设置全局语言环境都没有成功.我该怎么办?

so, clearly the locale is not being taken into account. I even try to set the global locale with no success. What can I do?

推荐答案

std :: toupper假定为​​1:1转换，因此从ß到SS的情况(没有Boost.StringAlgo)都没有希望.

std::toupper assumes a 1:1 conversion, so there is no hope for the ß to SS case, Boost.StringAlgo or not.

查看 StringAlgo的代码，我们看到它确实使用语言环境(似乎Borland除外).因此，对于另一种情况，我很好奇:您的平台上toupper('ó', std::locale("es_CO.UTF-8"))的结果是什么?

Looking at StringAlgo's code, we see that it does use the locale (Except on Borland, it seems). So, for the other case, I'm curious: What is the result of toupper('ó', std::locale("es_CO.UTF-8"))on your platform?

以上内容使我想到了其他事情:源代码中字符串的编码是什么? UTF8?在这种情况下，std :: toupper将看到两个代码单元ó"，因此没有希望.拉丁文1?在这种情况下，使用名为".UTF-8"的语言环境是不一致的.

Writing the above makes me think about something else: What is the encoding of the strings in your sources? UTF8? In that case, std::toupper will see two code units for 'ó', so there is no hope. Latin1? In that case, using a locale named ".UTF-8" is inconsistent.

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