java将十进制转换为任何二进制位 [英] java-convert decimal to any binary bit
问题描述
我正在做一个将十进制数字转换为二进制的项目。但是我有一个问题,如何将任何输入的数字转换为二进制(我正在使用数组),这是我的代码:
I'm making a project of converting decimal number into binary. But I have a problem that how can I convert any entered number into binary (I'm using array), here is my code:
public void Decimal2Binary(int a)
{
int result []=new int[8];
for (int i = 7;i >=0; i--,a/=2) {
result[i]=a%2;
}
我只需要8位二进制结果就不需要它,我需要任何大小的东西。
I do not need it for just only 8-bit binary result, yet, I need it for any size.
推荐答案
您实际上并没有指定输出,但是就可以了。
You don't actually specify the output, but here goes.
假定未签名(看起来像您一样)。
assuming unsigned (as it looks like you have).
StringBuilder result = new StringBuilder();
while(a > 0) {
result.append(a % 2);
a = a / 2; // This will round down automatically. ;)
}
如果您需要处理负数,我会使用&运算符-您也可以使用>>进行除法,但我将优化保留在编译器中,以使源代码更具可读性。
If you need to handle negative numbers, I would do bitwise comparisons using the & operator - you could also use >> for the division, but I am leaving that optimisation for the compiler to keep the source more readable.
显然,您可以更改到任何形式的追加
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