可以将默认析构函数自动生成为虚拟析构函数吗? [英] Can the default destructor be generated as a virtual destructor automatically?
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问题描述
默认析构函数可以自动生成为虚拟析构函数吗?
Can the default destructor be generated as a virtual destructor automatically?
如果我定义了一个基类但没有默认析构函数,那么是否存在默认虚拟析构函数
是自动生成的吗?
If I define a base class but no default destructor, is there a default virtual destructor generated automatically?
推荐答案
否。将方法虚拟化会带来成本,C ++的理念是不让您为未明确声明要使用的东西付费。如果将自动生成虚拟析构函数,那么您将自动付出代价。
No. There is a cost associated with making a method virtual, and C++ has a philosophy of not making you pay for things that you don't explicitly state that you want to use. If a virtual destructor would have been generated automatically, you would have been paying the price automatically.
为什么不只定义一个空的虚拟析构函数?
Why not just define an empty virtual destructor?
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