仅当单词以子字符串开头时，才在句子中查找子字符串的出现 [英] Find occurrence of substring in sentence only if word starts with substring

问题描述

如果我有2个字符串: 我的名字叫埃里克" 美国很棒"

If I have 2 strings: "My name is Eric" "America is great"

我的子字符串是'eri'.

And my substring is 'eri'.

我该如何编写一个只对第一句话返回true的函数，因为它有一个以eri(Eric)开头的单词，而不仅仅是eri(AmERIca).

How can I write a function that will only return true for the first sentence, because it has a WORD that starts with eri (Eric) and does not just contain eri (AmERIca).

注意； 我一直在使用NSPredicates，但是使用CONTAINS会返回两个值，而使用BEGINSWITH只会检查第一个单词.

Note; I have been using NSPredicates, but using CONTAINS would return both, and using BEGINSWITH would only check the first word.

此字符串也包含在一个对象中，例如，该属性称为， 所以我当前的代码是:

This string is also contained in an Object, say and the property is called , so my current code is:

NSPredicate *resultPredicate = [NSPredicate 
                                    predicateWithFormat:@"SELF.name contains[cd] %@",
                                    searchText];

searchResults = [[myArray filteredArrayUsingPredicate:resultPredicate] mutableCopy];

推荐答案

为什么不搜索带有前导空格的字符串，例如"eri"?这样只会自动找到实际的单词，而不会找到中间的单词.

Why not search for a string with leading space, like " eri"? That will automatically only find actual words and not something in the middle.

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