如何传递bash中包含空格的变量作为循环参数? [英] How to pass a variable containing space in bash as a loop argument?

问题描述

美好的一天，我正在创建一个脚本来读取路径的子文件夹/目录的一级.脚本是这样的:

 #loopdir.sh为我在`ls -d $ 1`中做回声$ i完毕 

但是，当我尝试使用它读取/media/My \ Passport/时，它会将参数读取为两个不同的目录:

  $ ./loopdir.sh/media/My \ Passport/ls:无法访问/media/My:没有此类文件或目录护照/ 

解决方案

尝试代替执行此操作(我的理解是您要列出子目录，对吗?):

  for i in"$ 1"/*;做回显"$ {i％/}"完毕 

解析 ls 输出是一个坏主意:它是用于交互式查看文件信息的工具.它的输出是为人类格式化的，将导致脚本中的错误.使用glob或find代替.了解原因: http://mywiki.wooledge.org/ParsingLs

(最后但并非最不重要):使用更多报价！<​​/strong>它们至关重要.另外，了解'和'和`之间的区别.请参见 http://mywiki.wooledge.org/Quotes和 http://wiki.bash-hackers.org/syntax/words

good day, I am creating a script to read one level of subfolders/directories of a path. The script is like so:

#loopdir.sh
for i in `ls -d $1`
do
echo $i
done

But when I tried to use it to read /media/My\ Passport/, it reads the argument as two different dirs:

$ ./loopdir.sh /media/My\ Passport/
ls: cannot access /media/My: No such file or directory
Passport/

解决方案

Try doing this instead (my understanding is that you want to list subdirs, Am I right?) :

for i in "$1"/*; do
    echo "${i%/}"
done

Parsing ls output is a bad idea : it's is a tool for interactively looking at file information. Its output is formatted for humans and will cause bugs in scripts. Use globs or find instead. Understand why: http://mywiki.wooledge.org/ParsingLs

And (last but not least) : USE MORE QUOTES! They are vital. Also, learn the difference between ' and " and `. See http://mywiki.wooledge.org/Quotes and http://wiki.bash-hackers.org/syntax/words

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