为什么代码没有删除"u"?从输入字符串? [英] Why is the code is not removing "u" from the input string?

问题描述

我正在学习C ++.今天，我已经编写了一个代码，以删除字符串中的元音.在某些测试中它工作正常.但是该测试未能消除"u"标记.从一个字符串.我的输入是: tour .输出为: tur .但是我期望像 tr 这样的输出用于 tour

I am learning C++. Today I have written a code to remove vowels form a string. It works fine in some tests. But this test is failing to remove "u" from a string. My input was: tour. Output was: tur. But I am expecting the output like tr for tour

代码:

#include <bits/stdc++.h>
using namespace std;

int main()
{
    string word;
    getline(cin, word);
    transform(word.begin(), word.end(), word.begin(), ::tolower);  // Converting uppercase to lowercase
    for (int i = 0; i < word.length(); i++)
    {
        if (word[i] == 'a' || word[i] == 'e' || word[i] == 'i' || word[i] == 'o' || word[i] == 'u')
        {
            word.erase(word.begin() + i);  // Removing specific character
        }
    }
    cout << word << endl;

    return 0;
}

我该怎么做?代码中的问题在哪里?

How can I do that? Where is the problem in the code?

推荐答案

擦除后，执行 i ++ .这意味着支票会绕过一个元素.

After erase, i++ is performed. That means one element is bypassed by the check.

将 for 循环更改为

for (int i = 0; i < word.length(); )
{
    if (word[i] == 'a' || word[i] == 'e' || word[i] == 'i' || word[i] == 'o' || word[i] == 'u')
    {
        word.erase(word.begin() + i);  // Removing specific character
    } 
    else 
    {
        i++; // increment when no erasion is performed
    }
}

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