如何在C ++ 11中创建正态整数分布? [英] How can I create a normal integer distribution in C++11?

问题描述

正态分布: std :: normal_distribution< T> 只接受实数类型，例如 float 或 double ，为什么它不接受整数类型?

The normal distribution: std::normal_distribution<T> only accepts a real-valued type such as float or double, why doesn't it accept an integer type?

如何创建正态整数分布?

How can I create a normal integer distribution?

推荐答案

我对C ++ 11几乎一无所知，但是我了解一点数学(或者我曾经做过一点)，离散的正态分布称为二项分布.实际上，当让 n 变为无穷大时，正态分布就是二项分布.

I know next to nothing about C++11 but I know a little math (or I did at one point) and a discrete normal distribution is called a Binomial distribution. In fact a normal distribution is the binomial distribution when you let n go to infinity.

因此，假设C ++ 11具有二项式分布，则您具有离散的正态分布.为什么不尝试 std :: binomial_distribution ?

So assuming C++11 has a binomial distribution then you have a discrete normal distribution. Why don't you try std::binomial_distribution?

您可能还想阅读 de Moivre–Laplace定理.

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