C ++-用于原始指针的reinterpret_cast的安全性 [英] C++ - Safety of reinterpret_cast for pointer-to-primitives

问题描述

我在我正在评估的项目中遇到了一段代码，想知道以下类型的转换是否安全:

I've come across a piece of code in a project I'm evaluating, and wanted to know if the following cast is safe:

void func(unsigned long* input);
...
int data = 42;
func(reinterpret_cast<unsigned long*>(&data));  
// Casting to remove compiler warnings about data type not matching type expected

我知道，仅通过简单的C样式转换(即(unsigned long *)& data )就可以解决麻烦. reinterpret_cast 是否自动使这种类型的转换操作安全?

I know that with just simple C-style casting (ie: (unsigned long*)&data) that this is asking for trouble. Does reinterpret_cast automagically make this type of casting operating safe?

谢谢.

推荐答案

不，这并不安全:程序行为未定义.

No it is not safe: the program behaviour is undefined.

这是因为指针类型无关.

This is because the pointer types are unrelated.

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