Windows上的GSL链接 [英] GSL linkage on Windows

问题描述

我正在尝试从GSL文档中编译示例.Windows，在conda下安装了Cmake + MSVS + GSL 2.6.

I am trying to compile examples from GSL documentation. Windows, Cmake + MSVS + GSL 2.6 installed under conda.

基本示例已编译并可以正常工作:

Basic example gets compiled and works just fine:

cmake_minimum_required(VERSION 3.15)
project(test)

find_package(GSL REQUIRED)

add_executable(test)
target_sources(test PRIVATE main.cpp)
target_include_directories(test PRIVATE "${GSL_INCLUDE_DIRS}")
target_link_libraries(test "${GSL_LIBRARIES}")

#include <stdio.h>
#include <gsl/gsl_sf_bessel.h>

int main (void)
{
    double x = 5.0;
    double y = gsl_sf_bessel_J0 (x);
    printf ("J0(%g) = %.18e\n", x, y);
    return 0;
}

但是此失败，并带有链接错误:

But this one fails with a linkage error:

错误LNK2001:无法解析的外部符号gsl_odeiv2_step_rk8pd

#include <stdio.h>
#include <gsl/gsl_errno.h>
#include <gsl/gsl_matrix.h>
#include <gsl/gsl_odeiv2.h>

int
func (double t, const double y[], double f[],
      void *params)
{
    (void)(t); /* avoid unused parameter warning */
    double mu = *(double *)params;
    f[0] = y[1];
    f[1] = -y[0] - mu*y[1]*(y[0]*y[0] - 1);
    return GSL_SUCCESS;
}

int
jac (double t, const double y[], double *dfdy,
     double dfdt[], void *params)
{
    (void)(t); /* avoid unused parameter warning */
    double mu = *(double *)params;
    gsl_matrix_view dfdy_mat
            = gsl_matrix_view_array (dfdy, 2, 2);
    gsl_matrix * m = &dfdy_mat.matrix;
    gsl_matrix_set (m, 0, 0, 0.0);
    gsl_matrix_set (m, 0, 1, 1.0);
    gsl_matrix_set (m, 1, 0, -2.0*mu*y[0]*y[1] - 1.0);
    gsl_matrix_set (m, 1, 1, -mu*(y[0]*y[0] - 1.0));
    dfdt[0] = 0.0;
    dfdt[1] = 0.0;
    return GSL_SUCCESS;
}

int
main (void)
{
    double mu = 10;
    gsl_odeiv2_system sys = {func, jac, 2, &mu};

    gsl_odeiv2_driver * d =
            gsl_odeiv2_driver_alloc_y_new (&sys, gsl_odeiv2_step_rk8pd,
                                           1e-6, 1e-6, 0.0);
    int i;
    double t = 0.0, t1 = 100.0;
    double y[2] = { 1.0, 0.0 };

    for (i = 1; i <= 100; i++)
    {
        double ti = i * t1 / 100.0;
        int status = gsl_odeiv2_driver_apply (d, &t, ti, y);

        if (status != GSL_SUCCESS)
        {
            printf ("error, return value=%d\n", status);
            break;
        }

        printf ("%.5e %.5e %.5e\n", t, y[0], y[1]);
    }

    gsl_odeiv2_driver_free (d);
    return 0;
}

gsl_odeiv2_step_rk8pd 在GSL中的某处定义如下: GSL_VAR const gsl_odeiv2_step_type * gsl_odeiv2_step_rk8pd; ，其中 GSL_VAR 表示外部.

gsl_odeiv2_step_rk8pd is defined somewhere in GSL like this: GSL_VAR const gsl_odeiv2_step_type *gsl_odeiv2_step_rk8pd;, where GSL_VAR means extern.

我想念什么?

推荐答案

您需要使用vcpkg重新编译gsl源代码.vcpkg可以使用CMake自动编译gsl.请google vcpkg.这很容易，没有错误.

you need re-compile the gsl source codes using vcpkg . vcpkg can compile gsl automatically with CMake. Please google vcpkg. it is very easy and no mistakes.

这篇关于Windows上的GSL链接的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！