类型错误：__init __（）至少需要4个非关键字参数（3给出） [英] TypeError: __init__() takes at least 4 non-keyword arguments (3 given)

问题描述

建议，请：）

当我使用这个脚本：

class CustomStreamListener(tweepy.StreamListener):

    def on_status(self, status):

        # We'll simply print some values in a tab-delimited format
        # suitable for capturing to a flat file but you could opt 
        # store them elsewhere, retweet select statuses, etc.



        try:
            print "%s\t%s\t%s\t%s" % (status.text, 
                                      status.author.screen_name, 
                                      status.created_at, 
                                      status.source,)
        except Exception, e:
            print >> sys.stderr, 'Encountered Exception:', e
            pass

    def on_error(self, status_code):
        print >> sys.stderr, 'Encountered error with status code:', status_code
        return True # Don't kill the stream

    def on_timeout(self):
        print >> sys.stderr, 'Timeout...'
        return True # Don't kill the stream

# Create a streaming API and set a timeout value of 60 seconds.

streaming_api = tweepy.streaming.Stream(auth, CustomStreamListener(), timeout=60)

# Optionally filter the statuses you want to track by providing a list
# of users to "follow".

print >> sys.stderr, 'Filtering the public timeline for "%s"' % (' '.join(sys.argv[1:]),)

streaming_api.filter(follow=None, track=Q)

有这样的错误：

Traceback (most recent call last):
  File "C:/Python26/test.py", line 65, in <module>
    streaming_api = tweepy.streaming.Stream(auth, CustomStreamListener(), timeout=60)
TypeError: __init__() takes at least 4 non-keyword arguments (3 given)

我应该怎么做呢？

What should I do then?

推荐答案

您的例子似乎是从<一个href=\"http://answers.oreilly.com/topic/2605-how-to-capture-tweets-in-real-time-with-twitters-streaming-api/\"相对=nofollow>此处。并且使用的是 Tweepy ，一个Python库用于访问Twitter的API。

Your example appears to be from here. And you are using Tweepy, a Python library for accessing the Twitter API.

从GitHub，这里是一个定义的流（）对象（假设你有最新版本的Tweepy的，请仔细检查！）

From Github, here is the definition of a Stream() object (assuming you have the latest version of Tweepy, please double check!),

def __init__(self, auth, listener, **options):
        self.auth = auth
        self.listener = listener
        self.running = False
        self.timeout = options.get("timeout", 300.0)
        self.retry_count = options.get("retry_count")
        self.retry_time = options.get("retry_time", 10.0)
        self.snooze_time = options.get("snooze_time",  5.0)
        self.buffer_size = options.get("buffer_size",  1500)
        if options.get("secure"):
            self.scheme = "https"
        else:
            self.scheme = "http"

        self.api = API()
        self.headers = options.get("headers") or {}
        self.parameters = None
        self.body = None

由于你似乎对参数的适当数量的已经过去了，它看起来像 CustomStreamListener（）不被初始化，因此不被传递到流（）类作为一个参数。看看你是否可以初始化一个 CustomStreamListener（）之前，作为参数传递给流（）。

Because you seemed to have passed in the appropriate number of arguments, it looks like CustomStreamListener() isn't being initialized, and therefore isn't being passed to the Stream() class as an argument. See if you can initialize a CustomStreamListener() prior to being passed as an argument to Stream().

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