向量< int>v(istream_iterator< int(cin)，istream_iterator< int>()); [英] vector<int> v(istream_iterator<int>(cin), istream_iterator<int>());

问题描述

#include <iostream>
#include <vector>
#include <iterator>
#include <algorithm>
using namespace std;

int main()
{
    vector<int> v(istream_iterator<int>(cin), istream_iterator<int>()); //Compilation error?!
    copy(v.begin(), v.end(), ostream_iterator<int>(cout, "\n"));

    return 0;
}

为什么该行出错?我知道编译器将"v"作为函数！很棒...

Why that line goes error? I know the compiler thouht 'v' as a function! Amazing...

推荐答案

此问题被称为C ++的最烦人的问题解析.

This problem is known as C++'s most vexing parse.

尝试将第一行更改为以下内容(注意多余的括号):

Try changing the first line to the following (note the extra parentheses):

vector<int> v((istream_iterator<int>(cin)), istream_iterator<int>());

这篇关于向量< int>v(istream_iterator< int(cin)，istream_iterator< int>());的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！