使用grep时获取行号 [英] Get line number while using grep

问题描述

我正在使用grep递归在文件中搜索字符串，所有匹配的文件和包含该字符串的行都在终端上打印.但是也有可能获得这些行的行号吗?

I am using grep recursive to search files for a string, and all the matched files and the lines containing that string are print on the terminal. But is it possible to get the line numbers of those lines too??

ex:目前我得到的是/var/www/file.php:$ options ="this.target" ，但是我要获取的是/var/www/file.php:1142 $ options ="this.target"; ，其中 1142 是包含该字符串的行号.

ex: presently what I get is /var/www/file.php: $options = "this.target", but what I am trying to get is /var/www/file.php: 1142 $options = "this.target";, well where 1142 would be the line number containing that string.

我用来递归grep的语法是 sudo grep -r'pattern''/var/www/file.php'

Syntax I am using to grep recursively is sudo grep -r 'pattern' '/var/www/file.php'

另一个问题是，如何获得不等于模式的结果.像所有文件一样，但不像具有特定字符串的文件一样?

One more question is, how do we get results for not equal to a pattern. Like all the files but not the ones having a certain string?

推荐答案

grep -n SEARCHTERM file1 file2 ...

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