使用 grep 时获取行号 [英] Get line number while using grep

问题描述

我使用 grep 递归搜索文件中的字符串，所有匹配的文件和包含该字符串的行都打印在终端上.但是是否也可以获得这些行的行号??

I am using grep recursive to search files for a string, and all the matched files and the lines containing that string are print on the terminal. But is it possible to get the line numbers of those lines too??

例如:目前我得到的是 /var/www/file.php: $options = "this.target"，但我想得到的是 /var/www/file.php: 1142 $options = "this.target";，其中 1142 将是包含该字符串的行号.

ex: presently what I get is /var/www/file.php: $options = "this.target", but what I am trying to get is /var/www/file.php: 1142 $options = "this.target";, well where 1142 would be the line number containing that string.

我用来递归 grep 的语法是 sudo grep -r 'pattern' '/var/www/file.php'

Syntax I am using to grep recursively is sudo grep -r 'pattern' '/var/www/file.php'

还有一个问题是，我们如何得到不等于模式的结果.喜欢所有文件，但不是那些具有特定字符串的文件?

One more question is, how do we get results for not equal to a pattern. Like all the files but not the ones having a certain string?

推荐答案

grep -n SEARCHTERM file1 file2 ...

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