使用 grep 仅报告行号 [英] Use grep to report back only line numbers

问题描述

我有一个可能包含错误格式的文件(在本例中，出现了模式 \backslash).我想使用 grep 仅返回发生这种情况的行号(例如，匹配就在这里，转到第 x 行并修复它).

I have a file that possibly contains bad formatting (in this case, the occurrence of the pattern \backslash). I would like to use grep to return only the line numbers where this occurs (as in, the match was here, go to line # x and fix it).

但是，似乎没有办法打印行号 (grep -n) 而不是匹配或行本身.

However, there doesn't seem to be a way to print the line number (grep -n) and not the match or line itself.

我可以使用另一个正则表达式来提取行号，但我想确保 grep 不能自己完成.我认为 grep -no 最接近，但仍然显示匹配.

I can use another regex to extract the line numbers, but I want to make sure grep cannot do it by itself. grep -no comes closest, I think, but still displays the match.

推荐答案

尝试:

grep -n "text to find" file.ext | cut -f1 -d:

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