使用grep只回报行号 [英] Use grep to report back only line numbers

问题描述

我有一个可能包含错误格式的文件（在这种情况下，模式的出现<我希望使用 grep 来仅返回发生这种情况的行号（例如，匹配在这里，请到＃行并修复它）。

但是，似乎没有办法打印行号（ grep -n ），而不是匹配或线本身。

我可以使用另一个正则表达式来提取行号，但我想确保grep不能自行完成。 grep -no 最接近，我想，但仍显示匹配。

解决方案

试试这个：

  grep -ntext找到file.ext | cut -f1 -d：
  

I have a file that possibly contains bad formatting (in this case, the occurrence of the pattern \\backslash). I would like to use grep to return only the line numbers where this occurs (as in, the match was here, go to line # x and fix it).

However, there doesn't seem to be a way to print the line number (grep -n) and not the match or line itself.

I can use another regex to extract the line numbers, but I want to make sure grep cannot do it by itself. grep -no comes closest, I think, but still displays the match.

解决方案

try this:

grep -n "text to find" file.ext |cut -f1 -d:

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