多的iOS开发者帐户 [英] Multiple iOS Developer Accounts

问题描述

如果我和另一个人要发布的应用程序，我们就必须以某种方式建立一个共同账户，我理解这一点。然而，在未来，如果我们能够独立发布应用程序，这需要我们去创造每一个另一个开发帐号，并因此花费另外$ 99个年度。所以我的问题是：有没有什么办法，我们既可以拥有个人账户，并以某种方式共同发布联合应用进入市场？

If I and another individual want to publish an application, we would have to somehow create a joint account, and I understand this. However, in the future, if we were to independently publish applications, that would require us to create another developer account each and thus spend another $99 yearly. So my question is: Is there any way where we can both have individual accounts and somehow jointly publish the joint application onto the market?

所以基本上，有没有什么办法，以避免简单地发布为我们个人的出版企业和联名账户单独帐户的有一个应用程序？

So essentially, is there any way to avoid having to create seperate accounts for our individual publishing ventures and a joint account simply for publishing one application?

不好意思，我是新来的iPhone发展，所以我可能错过了一些东西。

Sorry, I am new to iPhone Development so I may have missed something.

推荐答案

您的开发者ID是从你的iOS开发者计划认购一个独立的东西，你的ID可以是几个不同的开发人员计划订阅的成员。但是，如果你想拥有的不仅仅是一个帐户更多的开发者计划的订阅，你必须注册成为一个公司，而不是作为一个单独的。如果你这样做，你可以同时添加你的ID对共享的程序订阅。 （但是，你必须实际上有一个公司，注册）

Your developer ID is a separate thing from your iOS developer program subscription, and your ID can be a member of several different developer program subscriptions. However, if you want to have more than just one account on your developer program subscription, you'll have to sign up as a company rather than as an individual. If you do that, you can add both your ID's to the shared program subscription. (However, you'll have to actually have a company to sign up with.)

有三个独立的个人订阅可能是最容易的，最便宜的方式。如果$ 99是一个障碍，你可能不是所有的摆在首位建设一个产品那么严重。反之，如果你建立一个人们愿意购买一个坚实的产品，$ 99个订阅费不应该是一个问题。

Having three separate individual subscriptions is probably the easiest, cheapest way to go. If the $99 is really an obstacle, you're probably not all that serious about building a product in the first place. And conversely, if you build a solid product that people want to buy, the $99 subscription fee shouldn't be a problem.

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