单行计算在Java中的String []字符串中出现的次数? [英] One-liner to count number of occurrences of String in a String[] in Java?
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问题描述
我字符串
的数组:
String[] myArray = {"A", "B", "B", "C"};
是否有一个快速的方法来计算该阵列中字符串出现的次数?是的,我知道我可以遍历和执行COUNT自己:
Is there a quick way to count the number of occurrences of a string in that array? Yes, I know I can iterate and do the count myself:
int count = 0;
String whatToFind = "B";
for (String s : myArray) {
if (s.equals(whatToFind)) {
++count;
}
}
但我想知道是否有这个效用函数。我无法找到阵列
或 ArrayUtils
东西。是否有可能有一个班轮做到这一点?
But I was wondering if there was a utility function for this. I couldn't find anything in Arrays
or ArrayUtils
. Is it possible to do this with a one-liner?
推荐答案
您可以使用<一个href=\"http://docs.oracle.com/javase/7/docs/api/java/util/Collections.html#frequency%28java.util.Collection,%20java.lang.Object%29\"相对=nofollow>在频率
方法:
You can use the frequency
method:
List<String> list = Arrays.asList(myArray);
int count = Collections.frequency(list, "B");
或在一行:
int count = Collections.frequency(Arrays.asList(myArray), "B");
在Java 8还可以这样写:
With Java 8 you can also write:
long count = Arrays.stream(myArray).filter(s -> "B".equals(s)).count();
或用一个方法参照:
long count = Arrays.stream(myArray).filter("B"::equals).count();
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