确定Java中的用户提供的阵列的最大值和平均值 [英] Determining Maximum and Mean of an User-Provided Array in Java

问题描述

我是新来的编码所以很容易在我身上。我试图确定最大和使用两个单独的类（即某某单独xyztester类）的用户提供数组的意思。我已经有我的编码，但最大的输出是0.0，且平均输出比阵列的长度少一个。这里是我的编码 -

I am new to coding so be easy on me. I am trying to determine the maximum and mean of an user-provided array using two separate classes (i.e. xyz and a separate xyztester class). I've have my coding but the maximum output is 0.0 and the mean output is one less than the length of the array. Here is my coding -

XYZ类

public static double maximum(double[] array){
    double max = array[0];
    for (int j = 1; j < array.length; j++){
        if(array[j] > max){
            max = array[j];
        }
    }
    return max;
}

public static double mean(double[] array){
    double sum = 0;
    for (double k = 0; k < array.length; k++)
        sum = sum + array.length;

    double avg = sum / array.length;

    return avg;
}

xyzTester级

"xyzTester" class

    double [] b;
    b = new double [quantArray];

    int j;
    for (j = 0; j > quantArray; j++){
        b[j] = in.nextDouble();
    }
    double n = xyz.maximum(b);

    double [] c;
    c = new double [quantArray];

    int k;
    for (k = 0; k > quantArray; k++){
        c[k] = in.nextDouble();
    }
    double o = xyz.mean(c);

有人可以详细说一下我做错了？

Can someone detail what I am doing wrong?

推荐答案

我看到了两个问题：在平均法

I see two problems:In the mean method

sum = sum + array.length;

也许应该是

sum = sum + array[k];

其次所有浮点计算应该是浮点operants之间。因此，更好地施放的东西像数组的长度来划分之前增加一倍：

Secondly all floating point calculations should be between floating point operants. So better cast stuff like array length to double before dividing:

double avg = sum / (double)array.length;

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