如何将 xml 转换为请求的 xml [英] How to transform xml to requested one

问题描述

我有一个 xml，我必须将它转换为另一种 xml 结构.我尝试了很多方法，但没有成功.我需要使用 xslt 1.0.我问了一个问题，但我问后格式改变了.

I have an xml which I must transform it to another structure of xml. I tried many ways but no success. I need to use xslt 1.0. I asked a question but the format is changed after I asked.

输入:

<?xml version="1.0" encoding="ISO-8859-1"?>
<PersonBody>
    <Person>
        <D>Name</D>
        <D>Surname</D>
        <D>Id</D>
    </Person>
    <PersonValues>
        <D>Michael</D>
        <D>Jackson</D>
        <D>01</D>
    </PersonValues>
    <PersonValues>
        <D>James</D>
        <D>Bond</D>
        <D>007</D>
    </PersonValues>
    <PersonValues>
        <D>Kobe</D>
        <D>Bryant</D>
        <D>24</D>
    </PersonValues>
</PersonBody>

所需输出:

<?xml version="1.0" encoding="ISO-8859-1"?>
<PersonBody>
    <Persons>
        <Person>
            <Name>Michael</Name>
            <Surname>Jackson</Surname>
            <Id>1</Id>
        </Person>
        <Person>
            <Name>James</Name>
            <Surname>Bond</Surname>
            <Id>007</Id>
        </Person>
        <Person>
            <Name>Kobe</Name>
            <Surname>Bryant</Surname>
            <Id>24</Id>
        </Person>
    </Persons>
</PersonBody>

推荐答案

应该这样做:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>
  <xsl:key name="kColumnName" match="Person/*"
           use="count(preceding-sibling::*)" />

  <xsl:template match="@* | node()">
    <xsl:copy>
      <xsl:apply-templates select="@* | node()"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="/*">
    <xsl:copy>
      <Persons>
        <xsl:apply-templates select="PersonValues" />
      </Persons>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="PersonValues">
    <Person>
      <xsl:apply-templates select="*" />
    </Person>
  </xsl:template>

  <xsl:template match="PersonValues/*">
    <xsl:element name="{key('kColumnName', position() - 1)}">
      <xsl:apply-templates />
    </xsl:element>
  </xsl:template>
</xsl:stylesheet>

在您的示例输入上运行时，结果是:

When run on your sample input, the result is:

<PersonBody>
  <Persons>
    <Person>
      <Name>Michael</Name>
      <Surname>Jackson</Surname>
      <Id>01</Id>
    </Person>
    <Person>
      <Name>James</Name>
      <Surname>Bond</Surname>
      <Id>007</Id>
    </Person>
    <Person>
      <Name>Kobe</Name>
      <Surname>Bryant</Surname>
      <Id>24</Id>
    </Person>
  </Persons>
</PersonBody>

这篇关于如何将 xml 转换为请求的 xml的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！