Bash 脚本 - 迭代 find 的输出 [英] Bash Script - iterating over output of find

问题描述

我有一个 bash 脚本，我需要在其中遍历 find 命令输出的每一行，但似乎我正在遍历 find 命令中的每个单词(空格分隔).到目前为止，我的脚本如下所示:

I have a bash script in which I need to iterate over each line of the ouput of the find command, but it appears that I am iterating over each Word (space delimited) from the find command. My script looks like this so far:

folders=`find -maxdepth 1 -type d`

for $i in $folders
do
    echo $i
done

我希望这会给出如下输出:

I would expect this to give output like:

./dir1 and foo
./dir2 and bar
./dir3 and baz

但我得到这样的输出:

./dir1
and
foo
./dir2
and
bar
./dir3
and
baz

我在这里做错了什么?

推荐答案

由于您没有使用 find 的任何更高级的功能，您可以使用一个简单的模式来遍历子目录:

Since you aren't using any of the more advanced features of find, you can use a simple pattern to iterate over the subdirectories:

for i in ./*/; do
    echo "$i"
done

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