bash脚本 - 遍历查找的输出 [英] Bash Script - iterating over output of find

问题描述

我有，我需要遍历find命令的输出中的每行一个bash脚本，但现在看来，我遍历从find命令每个单词（分隔空间）。我的脚本看起来像这样至今：

I have a bash script in which I need to iterate over each line of the ouput of the find command, but it appears that I am iterating over each Word (space delimited) from the find command. My script looks like this so far:

folders=`find -maxdepth 1 -type d`

for $i in $folders
do
    echo $i
done

我希望这给像输出：

I would expect this to give output like:

./dir1 and foo
./dir2 and bar
./dir3 and baz

但我insted的获得输出是这样的：

But I am insted getting output like this:

./dir1
and
foo
./dir2
and
bar
./dir3
and
baz

我在做什么错在这里？

What am I doing wrong here?

推荐答案

找到，你可以使用一个简单的模式遍历子目录：

Since you aren't using any of the more advanced features of find, you can use a simple pattern to iterate over the subdirectories:

for i in ./*/; do
    echo "$i"
done

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