处理GCC警告和输出bash脚本 [英] Handling gcc warnings and output in a Bash Script

问题描述

所以，我是新来的整个bash脚本编程的场景，但我在一个脚本一起汇编目录中的所有的.c文件，我已经成功地这样做：

So I am new to the whole Bash scripting scene, but I am working on a script to compile all the .c files in a directory which I have succeeded in doing so by:

    for F in *.c; do
      gcc -c -Wall -o ${F%.c} $F
    done

一切工作正常，但我想输出看起来是这样的：

Everything works fine, but I want to the output to look something like:

ex1.c Errors
ex2.c OK
ex3.c Warnings

所以基本上我想有0退出状态（一切正常）为OK，状态1（警告，但没有错误）的警告和状态2（未编译）为错误。

So basically I want to have an exit status of 0 (Everything went fine) for "Ok", status 1 (Warnings, but no error) for "Warnings" and status 2 (Did not compile) for "Errors".

我有一个很难搞清楚如何做这样的事情。我周围中搜索，但没有找到任何东西，我发现是有用的。我很可能虽然忽略了什么。

I am having a hard time figuring out how to do such a thing. I've searched around and couldn't find anything that I have found to be useful. I very well could have overlooked something though.

编辑：会不会有反正说：如果GCC -Wall file.c中有错误，然后只是说错误的完整GCC错误处理的消息呢？同样的，警告和完美的编译？

Would there be anyway to say: if gcc -Wall file.c has errors, then just say Error instead of the full GCC error handling message? Same with warnings and a perfect compile?

推荐答案

GCC 收益 0 退出code表示警告，以及。所以，你要区分自己与这样的：

gcc returns 0 exit code for warnings as well. So you are going to differentiate that yourself with something like this:

  for F in *.c; do
      out=$(gcc -c -Wall -o ${F%.c} $F 2>&1)
      if [ $? -ne 0 ]; then
        echo $F Errors
      else
         if grep "warning:" <<<"${out}" >/dev/null ; then
          echo $F Warnings
        else
          echo $F OK
        fi
     fi
  done

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