使用 sed 或 awk 重复提取两个字符串之间的文本? [英] Extract text between two strings repeatedly using sed or awk?

问题描述

我有一个名为plainlinks"的文件，如下所示:

I have a file called 'plainlinks' that looks like this:

13080. ftp://ftp3.ncdc.noaa.gov/pub/data/noaa/999999-94092-2012.gz
13081. ftp://ftp3.ncdc.noaa.gov/pub/data/noaa/999999-94094-2012.gz
13082. ftp://ftp3.ncdc.noaa.gov/pub/data/noaa/999999-94096-2012.gz
13083. ftp://ftp3.ncdc.noaa.gov/pub/data/noaa/999999-94097-2012.gz
13084. ftp://ftp3.ncdc.noaa.gov/pub/data/noaa/999999-94098-2012.gz
13085. ftp://ftp3.ncdc.noaa.gov/pub/data/noaa/999999-94644-2012.gz
13086. ftp://ftp3.ncdc.noaa.gov/pub/data/noaa/999999-94645-2012.gz
13087. ftp://ftp3.ncdc.noaa.gov/pub/data/noaa/999999-94995-2012.gz
13088. ftp://ftp3.ncdc.noaa.gov/pub/data/noaa/999999-94996-2012.gz
13089. ftp://ftp3.ncdc.noaa.gov/pub/data/noaa/999999-96404-2012.gz

我需要生成如下所示的输出:

I need to produce output that looks like this:

999999-94092
999999-94094
999999-94096
999999-94097
999999-94098
999999-94644
999999-94645
999999-94995
999999-94996
999999-96404

推荐答案

使用sed:

sed -E 's/.*/(.*)-.*/1/' plainlinks

输出:

999999-94092
999999-94094
999999-94096
999999-94097
999999-94098
999999-94644
999999-94645
999999-94995
999999-94996
999999-96404

要保存对文件的更改，请使用 -i 选项:

To save the changes to the file use the -i option:

sed -Ei 's/.*/(.*)-.*/1/' plainlinks

或者保存到一个新文件然后重定向:

Or to save to a new file then redirect:

sed -E 's/.*/(.*)-.*/1/' plainlinks > newfile.txt

说明:

s/    # subsitution
.*    # match anything
/    # upto the last forward-slash (escaped to not confused a sed)
(.*)  # anything after the last forward-slash (captured in brackets)
-     # upto a hypen
.*    # anything else left on line
/     # end match; start replace 
1    # the value captured in the first (only) set of brackets
/     # end

这篇关于使用 sed 或 awk 重复提取两个字符串之间的文本?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！