C:是否有“懒惰的评价"?当使用 &&运算符，如在 C++ 中? [英] C : is there "lazy evaluation" when using && operator, as in C++?

问题描述

我想知道这看起来是否正确:

I would like to know if this looks correct :

while((next !=NULL) && (strcmp(next->name, some_string) < 0) {
    //some process
}

我的意思是，如果 next 是 NULL，那么表达式的第二部分就不会被编译器测试?我听说在 C++ 中就是这种情况(但我什至不确定).

I mean, if next is NULL, then the second part of the expression won't be ever tested by the compiler? I have heard that in C++ it's the case (but I'm not even sure of it).

有人可以确认我不会在某些编译器上遇到奇怪的错误吗?

Can someone confirm me that I won't get strange errors on some compilers with that?

推荐答案

是 && 短路了，你使用正确.
如果 next is NULL 字符串比较永远不会发生.

Yes && is short circuited and you are using it correctly.
If next is NULL string compare will never happen.

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