delete[] 是否等于删除? [英] Is delete[] equal to delete?

问题描述

IP_ADAPTER_INFO *ptr=new IP_ADAPTER_INFO[100];

如果我免费使用

delete ptr;

会不会导致内存泄露，如果不是那为什么?

will it lead to memory leak, if not then why ?

这是VS2005生成的反汇编代码

This is disassembly code generated by VS2005

; delete ptr;
0041351D  mov         eax,dword ptr [ptr] 
00413520  mov         dword ptr [ebp-0ECh],eax 
00413526  mov         ecx,dword ptr [ebp-0ECh] 
0041352C  push        ecx  
0041352D  call        operator delete (4111DBh) 
00413532  add         esp,4 

; delete []ptr;
00413535  mov         eax,dword ptr [ptr] 
00413538  mov         dword ptr [ebp-0E0h],eax 
0041353E  mov         ecx,dword ptr [ebp-0E0h] 
00413544  push        ecx  
00413545  call        operator delete[] (4111E5h) 
0041354A  add         esp,4 

推荐答案

这是否会导致内存泄漏、擦除硬盘、让你怀孕、让讨厌的鼻魔在你的公寓周围追赶你，或者让一切正常没有明显的问题，是未定义的.一个编译器可能会这样，另一个编译器会改变下午.或者它可能不会.

Whether this leads to a memory leak, wipes your hard disk, gets you pregnant, makes nasty Nasal Demons chasing you around your apartment, or lets everything work fine with no apparent problems, is undefined. It might be this way with one compiler, and change with another, change with a new compiler version, with each new compilation, with the moon phases, your mood, or depending on the number of neutrinos that passed through the processor on the last sunny afternoon. Or it might not.

所有这些，以及无数其他可能性都归为一个术语:未定义的行为:

All that, and an infinite number of other possibilities are put into one term: Undefined behavior:

远离它.

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