在java中十进制转换为二进制具有倒车订单的相关问题 [英] Converting decimal to binary in java having trouble with reversing order
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问题描述
哎,所以我把我的第一个CS当然永远在我的大学其在java中任教。我在遇到麻烦十进制转换为二进制。我似乎能够得到正确的输出,但其以相反的顺序,我不知道如何把它放在正确的顺序,这里就是我codeD到目前为止,
进口的java.util。*;
公共类{六硼化镧
公共静态无效的主要(字串[] args){
扫描仪输入=新的扫描仪(System.in);
System.out.print(输入一个十进制数转换为二进制:);
INT X = input.nextInt();
诠释Ÿ;
串Y1 =;
而(X!= 0){
Y = X%2;
X = X / 2;
Y1 = Integer.toString(Y);
System.out.print(Y1 +);
}
}
}
解决方案
看来你是显示仅在正确的顺序输出。但是如果你想扭转目前的输出,你可以使用下面code:
扫描仪输入=新的扫描仪(System.in);
System.out.print(输入一个十进制数转换为二进制:);
INT X = input.nextInt();
诠释Ÿ;
串Y1 =;
串反向=;
而(X!= 0){
Y = X%2;
X = X / 2;
Y1 = Integer.toString(Y);
// System.out.print(Y1 +);
反向= Y1 ++逆转;
}
的System.out.println(反向顺序:+反向);
Hey so I'm taking my first cs course ever at my university its taught in java. I'm having trouble converting decimal to binary. I seem to be able to get the correct output but its in reverse order, and I have no idea how to put it in the correct order, here is what I've coded so far,
import java.util.*;
public class lab6 {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter a decimal number to convert to binary: ");
int x = input.nextInt();
int y;
String y1="";
while(x!=0){
y=x%2;
x=x/2;
y1 = Integer.toString(y);
System.out.print(y1+" ");
}
}
}
解决方案
It seems you are showing the output in correct order only. But if you want to reverse the current output you can use below code:
Scanner input = new Scanner(System.in);
System.out.print("Enter a decimal number to convert to binary: ");
int x = input.nextInt();
int y;
String y1="";
String reverse = "";
while(x!=0){
y=x%2;
x=x/2;
y1 = Integer.toString(y);
// System.out.print(y1+" ");
reverse = y1+" "+reverse;
}
System.out.println("Reverse Order :"+reverse);
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