提高的unique_ptr的thread_group举动所有权线程 [英] boost thread_group move ownership of unique_ptr to thread

问题描述

有什么解决方法，使这一code运行？在code结果试图引用删除功能。 的unique_ptr 被分配在一个循环，然后传递到线程，后来摆脱了。

 的boost :: thread_group线程;
的std ::的unique_ptr＆LT; ScenarioResult＆GT; scenario_result;而（（scenario_result = scenarioStock.getNextScenario（））！= nullptr）
{
threads.create_thread（升压::绑定（安培;模拟:: RunSimulation，升压:: REF（grid_sim）的std ::移动（scenario_result）））;
}
 

解决方案

您可以使用lambda前pression而不是的boost ::绑定

  threads.create_thread（[安培] {grid_sim.RunSimulation（性病::移动（scenario_result））;}）;
 

与你在做什么的问题是， create_thread 试图复制仿函数来说，绑定创建和失败，因为的unique_ptr 绑定参数的presence使仿函数布展只。

What workaround exists to make this code run? The code results in "Attempting to reference a deleted function". unique_ptr is assigned in a loop and then passed on to thread and later got rid of.

boost::thread_group threads;
std::unique_ptr<ScenarioResult> scenario_result;

while ((scenario_result = scenarioStock.getNextScenario()) != nullptr)
{
threads.create_thread(boost::bind(&Simulation::RunSimulation, boost::ref(grid_sim), std::move(scenario_result)));
}

解决方案

You can use a lambda expression instead of boost::bind

threads.create_thread([&] { grid_sim.RunSimulation(std::move(scenario_result)); });

The problem with what you're doing is that create_thread attempts to copy the functor that bind creates, and that fails because the presence of the unique_ptr bound argument makes the functor move-only.

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