它是安全的假设，一个指针是在C int的大小？ [英] Is it safe to assume that a pointer is the size of an int in C?

问题描述

在设计一种新的编程语言，它是安全的假设，一个C int和指针是在机器上同样大小？

In designing a new programming language, is it safe to assume that a C int and a pointer are the same size on the machine?

推荐答案

没有。指针可能比大小的整数更大或更小。如果你需要传递一个指针出于某种原因的整数（如执行整数，而不是指针，算术），他们都保证能够装入的使用intptr_t 。

No. A pointer may be larger or smaller than an integer in size. If you need to pass a pointer as an integer for some reason (like performing integer, rather than pointer, arithmetic), they are guaranteed to fit into an intptr_t.

它们不能保证装配到一个为size_t作为另一个回答的建议，但在实践中这是不可能的，他们不会，因为最大可寻址尺寸通常等于最大可寻址的地址。

They are not guaranteed to fit into a size_t as suggested in another answer, but in practice it is unlikely that they won't, since the largest addressable size is usually equal to the largest addressable address.

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