如何在C ++中创建一个静态类？ [英] How do you create a static class in C++?

问题描述

如何在C ++中创建一个静态类？我应该能够做如下：

How do you create a static class in C++? I should be able to do something like:

cout << "bit 5 is " << BitParser::getBitAt(buffer, 5) << endl;

假设我创建了BitParser类。

Assuming I created the BitParser class. What would the BitParser class definition look like?

推荐答案

如果您正在寻找一种将static关键字应用于一个类，就像你可以在C＃中，例如，那么你将无法使用托管C ++。

If you're looking for a way of applying the "static" keyword to a class, like you can in C# for example, then you won't be able to without using Managed C++.

但是样本的外观，你只需要在BitParser对象上创建一个公共静态方法。像这样：

But the looks of your sample, you just need to create a public static method on your BitParser object. Like so:

BitParser.h

class BitParser
{
 public:
  static bool getBitAt(int buffer, int bitIndex);

  // ...lots of great stuff

 private:
  // Disallow creating an instance of this object
  BitParser() {}
};

BitParser.cpp

bool BitParser::getBitAt(int buffer, int bitIndex)
{
  bool isBitSet = false;
  // .. determine if bit is set
  return isBitSet;
}

您可以使用此代码以与示例相同的方式调用方法代码。

You can use this code to call the method in the same way as your example code.

希望有所帮助！干杯。

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