C ++ |生成10-20之间的伪数 [英] C++ | Generating a pseudo number between 10-20

问题描述

我正在做一个基于文本的C + + RPG，我试图找出如何计算出敌人击中你的伤害量。我的想法是这样的。

I am making a text-based C++ RPG and I am trying to figure out how to work out the amount of damage that the enemy hits you for. My idea is something like this.

Damage done = randomIntBetween10and20 * enemyLevel

Damage done = randomIntBetween10and20*enemyLevel

每次击中一个设定的金额，并允许有临界打击（例如，如果命中超过15我会把它作为一个危机打击）

This way it doesn't always hit for a set amount each time and allows there to be Critical Strikes (For example, if the hit is above 15 I would class that as a Critical Strike)

我是C ++的新手，所以我不太确定如何做到这一点，任何帮助将非常感激。

I'm new to C++ so I'm not quite sure how I can do this, any help would be greatly appreciated.

推荐答案

你应该从标题中省略真正的一词，因为你可能不是这个意思。您可能只需要一个伪随机号码。使用个人计算机几乎不可能实现真实的随机性。以下代码段将为您提供10..19（含）范围内的伪随机数：

You should omit the word "truly" from the title, because you probably don't mean it. You probably just want a pseudorandom number. True randomness is virtually impossible to achieve with a personal computer. The following snippet will give you a pseudorandom number in the range 10..19 inclusive:

#include<cstdlib>
#include<ctime>

// ...
srand(time(0));
int r = rand() % (20 - 10) + 10;

如果要在范围中包括20，则这是一个包含11个数字的范围：

If you want to include 20 in the range then this is a range of 11 numbers:

int r = rand() % (21 - 10) + 10

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