C ++查找i更改为ISO [英] C++ Lookup of i changed for ISO

问题描述

我有一个字典的以下代码。

  void Dictionary :: translate（char out_s []，const char []）
 {
 
 for（int i = 0; i  {
 if（strcmp（englishWord [i]，s） = 0）
 break; 
} 
 if（i  strcpy（out_s，elvishWord [i]）; 
  

这给出了错误 c $ c>并提到如果我使用 -fpermissive ，代码将被接受。

任何想法？

不要for iso（也许读取整个错误信息...

）

/ strong>），但是对于ISO C ++。问题是 i 变量的范围只是 for 循环（因为它的定义在初始化循环）。因为你似乎想在循环外使用它，所以这样声明：

  int i; 
 for（i = 0; i  // ... 
} 
 
 do_safe_stuff_with // valid 
  

I have the following code for a dictionary.

void Dictionary::translate(char out_s[], const char s[])
{

for (int i=0;i<numEntries;i++)
{
   if (strcmp(englishWord[i], s)==0)
       break;
}
if (i<numEntries)
strcpy(out_s, elvishWord[i]);

which gives me the error name lookup of i changed for iso and mentions that the code will be accepted if i use -fpermissive. If i try and initialize the variable outside the for loop it generates a whole load of errors.

Any ideas?

Thanks in advance.

解决方案

Not "for iso" (perhaps read the entire error message...), but for ISO C++. The problem is that the scope of the i variable is only the for loop (since its definition is inside the initialization of the loop). Since it seems you want to use it outside the loop, declare it like so:

int i;
for (i = 0; i < foo; i++) {
    // ...
}

do_safe_stuff_with(i); // valid

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