C ++：如何转换从浮点到字符串没有舍入，截断或填充？ [英] C++: How to Convert From Float to String Without Rounding, Truncation or Padding?

问题描述

我遇到问题，无法解决问题。需要帮助从古茹。下面是示例代码： -

I am facing a problem and unable to resolve it. Need help from gurus. Here is sample code:-

float f=0.01f;
printf("%f",f);

a。有什么办法，我们可以强制编译器为float类型的变量赋予相同的值？

a. Is there any way that we may force the compiler to assign same values to variable of float type?

b。我想将float转换为字符串/字符数组。如何才能将仅有且完全相同的值转换为字符串/字符数组。我想确保没有填充零，没有不必要的值被填充，没有像上面的例子中的数字改变。

b. I want to convert float to string/character array. How is it possible that only and only exactly same value be converted to string/character array. I want to make sure that no zeros are padded, no unwanted values are padded, no changes in digits as in above example.

推荐答案

除了非常少的值（例如0.25），使用基数2值不可能精确地表示一个十进制的十进制数。要得到你所需要的，你必须从float / double内置类型切换到某种十进制数字包。

It is impossible to accurately represent a base 10 decimal number using base 2 values, except for a very small number of values (such as 0.25). To get what you need, you have to switch from the float/double built-in types to some kind of decimal number package.

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