Rapidjson，在另一个数组的数组内部获取一个值 [英] Rapidjson , get a value inside an array of another array

问题描述

我需要用rapidjson稀释这种json：

I need to sparse a json of this kind with rapidjson :

{
    "errors":{},
    "id":2326625,
    "source_code":"GOOG",
    "data":
    [
        ["2010-01-12",-0.010565362832445,-0.010432881793793,-0.010144243731464,-0.017685262281432,-0.3275071624503],
        ["2010-01-13",-0.036084889870791,-0.016333087890756,-0.024003268530183,-0.0057299789787753,0.33911818660036],
        ["2010-01-14",0.012849006806501,0.0098673018033346,0.015523616828298,0.0047058823529412,-0.34735779281787],
        ["2010-01-15",0.013166015223205,-0.0010781671159029,-0.0081756037236783,-0.016698910497913,0.28200124010685]
    ]
}

要获得idsource_code的值非常简单：

To get value of id "source_code" quite simple :

d.Parse< 0>（json）;
的printf（source_code=％s\\\
，文件[source_code]的GetString（））;

但是我能不能成功检索数据的价值。举例来说，我想能够检索2010-01-12和-0.010565362832445（在数据中的第一阵列的两个第一值）。

However i can't succeed to retrieve value of data. For instance, i would like to be able to retrieve "2010-01-12" and "-0.010565362832445" (The two first value of the first array in data).

你有什么想法？

推荐答案

请注意，数据是一个数组数组如果你想检索你上面说的话，请尝试：

Note that "data" is an array of arrays. If you want to retrieve what you said above, try this:

const rapidjson::Value& b = d["data"];

for (rapidjson::SizeType i = 0; i < b.Size(); i++)
{
    const rapidjson::Value& c = b[i];

    printf("%s \n",c[rapidjson::SizeType(0)]);
    printf("%.20f \n",c[rapidjson::SizeType(1)]);
}

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