如何从十六进制字符串创建UIColor? [英] How can I create a UIColor from a hex string?
本文介绍了如何从十六进制字符串创建UIColor?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如何使用十六进制字符串格式(如#00FF00
?
UIColor
解决方案
我发现最简单的方法是使用宏。
#define UIColorFromRGB(rgbValue)[UIColor colorWithRed:((float )(255)blue((float(rgbValue& 0xFF0000)> 16))/ 255.0 green:((float)((rgbValue& 0xFF00)> ))/ 255.0 alpha:1.0]
这个代码的格式化版本:
#define UIColorFromRGB(rgbValue)\
[UIColor colorWithRed:((float) ((rgbValue& 0xFFFFFF))> 16))/ 255.0 \
green:((float)((rgbValue& 0x00FF00)>> 8))/ 255.0 \
blue:((float)((rgbValue& 0x0000FF)> 0))/ 255.0 \
alpha:1.0]
用法:
label.textColor = UIColorFromRGB(0xBC1128);
How can I create a
UIColor
from a hexadecimal string format, such as#00FF00
?解决方案I've found the simplest way to do this is with a macro. Just include it in your header and it's available throughout your project.
#define UIColorFromRGB(rgbValue) [UIColor colorWithRed:((float)((rgbValue & 0xFF0000) >> 16))/255.0 green:((float)((rgbValue & 0xFF00) >> 8))/255.0 blue:((float)(rgbValue & 0xFF))/255.0 alpha:1.0]
Also formatted version of this code:
#define UIColorFromRGB(rgbValue) \ [UIColor colorWithRed:((float)((rgbValue & 0xFF0000) >> 16))/255.0 \ green:((float)((rgbValue & 0x00FF00) >> 8))/255.0 \ blue:((float)((rgbValue & 0x0000FF) >> 0))/255.0 \ alpha:1.0]
Usage:
label.textColor = UIColorFromRGB(0xBC1128);
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