如何通过Python中的字典值排序字典列表? [英] How do I sort a list of dictionaries by values of the dictionary in Python?
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问题描述
这个
我有一个字典列表,并希望按照该字典的值排序。
[{'name':'Homer','age':39},{'name':'Bart','age':10}]
按名称排序,应成为
[{'name':'Bart','age':10},{'name':'荷马','age':39}]
pre>
解决方案使用键而不是cmp看起来更清洁:
< pre class =lang-py prettyprint-override>newlist = sorted(list_to_be_sorted,key = lambda k:k ['name'])
或JFSebastian等人建议,
from operator import itemgetter
newlist = sorted(list_to_be_sorted,key = itemgetter('name'))
为了完整性(如fitzgeraldsteele的评论中指出的),添加 reverse = True
排序降序
newlist = sorted(l,key = itemgetter 'name'),reverse = True)
I got a list of dictionaries and want that to be sorted by a value of that dictionary.
This
[{'name':'Homer', 'age':39}, {'name':'Bart', 'age':10}]
sorted by name, should become
[{'name':'Bart', 'age':10}, {'name':'Homer', 'age':39}]
解决方案
It may look cleaner using a key instead a cmp:
newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])
or as J.F.Sebastian and others suggested,
from operator import itemgetter
newlist = sorted(list_to_be_sorted, key=itemgetter('name'))
For completeness (as pointed out in comments by fitzgeraldsteele), add reverse=True
to sort descending
newlist = sorted(l, key=itemgetter('name'), reverse=True)
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