如何grep查询两个字符串的所有文件 [英] How to grep query all files for two strings

问题描述

这里我们去：

我需要查询两个都有TODO语句和我的名字的php文件。
这两个字符串都可以在文档的任意位置（即行），并且可以放在0-无限行（位置0-n）的任何地方。

如何grep查询我的名字：
$ b

  find -name'*。 php'-exec grep -infincken{} + 
  

输出：

  ./ some / file.php：51：ramon fincken 
 ./somefile.php:2：rfincken 
  

如何为TODO查询grep

  find -name'* .php'-exec grep -nTODO{} + 
  

输出：

  ./ some / file.php：53：// TODO：foobar！ 
 ./some/otherfile.php:53：// TODO：foobar？ 
  

我需要结合两个grep查询（或其结果）我期待这样的结果：

$ p $ ./ some / file.php


我曾经在一个grep中尝试过运算符，但他们预计两个字符串在同一行上，并以特定的顺序或想出所有结果（OR .. OR）而不是（AND）

解决方案

这行看起来很难看，但它应该给你想要的东西： b
$ b

  find whatever ... | xargs grep -il'fincken'
 | xargs grep -il'todo'
 | xargs grep -in -e'todo'-e'fincken'
  

输出如下所示：

  / foo / bar / file：100：TODO 
 / foo / bar / file：101：fincken 
  

只有 TODO 和 fincken 将被列出。

Here we go:

I need to query php files which both have a TODO statement as well as my name. Both strings could be anywhere in the document (ie. line) and be positioned anywhere on 0-infinite lines (position 0-n).

How to grep query for my name:

find -name '*.php' -exec grep -in "fincken" {} +

output:

./some/file.php:51: ramon fincken
./somefile.php:2: rfincken

How to grep query for the TODOs

find -name '*.php' -exec grep -n "TODO" {} +

output:

./some/file.php:53: // TODO: foobar!
./some/otherfile.php:53: // TODO: foobar?

I need to combine both grep queries (or their results) so I am expecting this as result:

./some/file.php

I have tried operators in one grep, but they expected both strings on the same line and in a particular order or .. came up with all results (OR .. OR) instead of ( AND )

解决方案

this line looks ugly, but it should give what you want:

find whatever...|xargs grep -il 'fincken'
                |xargs grep -il 'todo'
                |xargs grep -in -e'todo' -e'fincken'  

The output would look like:

/foo/bar/file : 100:TODO
/foo/bar/file : 101:fincken

only files with both TODO and fincken would be listed.

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