在Go中删除切片中的字符串 [英] Removing a string from a slice in Go

问题描述

  strings：= [] string 
 strings = append（strings，one）
 strings = append（strings，two）
 strings = append（strings，three）
 中删除​​字符串two字符串？
解决方案
找到要移除的元素并将其从中移除任何其他切片。
 
 
 
发现它是一种线性搜索。删除是以下切片技巧之一：
  a = append（a [：i]，a [i + 1：] ...）
 //或
a = a [ ：i + copy（a [i：]，a [i + 1：]）] 
  
是完整的解决方案（在 Go Playground 上试用）：
  s：= [] string {one，two，three} 
 
 // Find and如果v ==two{
s = append（s [：i]，s [i + 1：]），则删除two
 for v，：range s {
。 ..）
 break 
} 
} 
 
 fmt.Println（s）//打印[one three] 
  
  
 
 
如果您想将其包装到一个函数中： 
 
 
  func remove（s [] string，r string）[] string {
 for i，v：= range s {
 if v == r {
 return append（s [： i]，s [i + 1：] ...）
} 
} 
返回s 
} 
  
 
 
 
使用它：
  s： = [] string {one，two，three} 
s = remove（s，two）
 fmt.Println（s）//打印[one three] 
  
 
I have a slice of strings, and I want to remove a specific one.
strings := []string
strings = append(strings, "one")
strings = append(strings, "two")
strings = append(strings, "three")
Now how can I remove the string "two" from strings?
解决方案
Find the element you want to remove and remove it like you would any element from any other slice.

Finding it is a linear search. Removing is one of the following slice tricks:
a = append(a[:i], a[i+1:]...)
// or
a = a[:i+copy(a[i:], a[i+1:])]
Here is the complete solution (try it on the Go Playground):
s := []string{"one", "two", "three"}

// Find and remove "two"
for i, v := range s {
    if v == "two" {
        s = append(s[:i], s[i+1:]...)
        break
    }
}

fmt.Println(s) // Prints [one three]
If you want to wrap it into a function:
func remove(s []string, r string) []string {
    for i, v := range s {
        if v == r {
            return append(s[:i], s[i+1:]...)
        }
    }
    return s
}
Using it:
s := []string{"one", "two", "three"}
s = remove(s, "two")
fmt.Println(s) // Prints [one three]


                        
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